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u^2-65u+64=0
a = 1; b = -65; c = +64;
Δ = b2-4ac
Δ = -652-4·1·64
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-63}{2*1}=\frac{2}{2} =1 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+63}{2*1}=\frac{128}{2} =64 $
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